React.js 与 OpenWeatherMap 结合,获取 weathers.map 不是一个函数
2022-03-04
341
我正在学习上大学的React.js,并且有点困扰。我遇到此错误:
074042406
我确定它很简单,但无法弄清楚!它是标准
create-react-app
,创建一个称为组件的目录,这两个文件现场存在:
weathers.js:
585152672
822173720
2个回答
您收到错误是因为 api 的结果不是数组。它是一个如下所示的对象(对于伦敦):
{
"coord": {
"lon": -0.1257,
"lat": 51.5085
},
"weather": [
{
"id": 500,
"main": "Rain",
"description": "light rain",
"icon": "10n"
}
],
"base": "stations",
"main": {
"temp": 278.91,
"feels_like": 276.51,
"temp_min": 277.25,
"temp_max": 280.02,
"pressure": 1021,
"humidity": 88
},
"visibility": 10000,
"wind": {
"speed": 3.09,
"deg": 330
},
"rain": {
"1h": 0.89
},
"clouds": {
"all": 100
},
"dt": 1646438029,
"sys": {
"type": 2,
"id": 2019646,
"country": "GB",
"sunrise": 1646375984,
"sunset": 1646415906
},
"timezone": 0,
"id": 2643743,
"name": "London",
"cod": 200
}
如果您想要结果中的
name
属性,您可以像这样获取它:
import {useState} from 'react'
import axios from 'axios'
import Weather from './Weather'
function Weathers() {
const [weathers, setWeathers] = useState()
const [city, setCity] = useState('')
const API = {
link: "http://api.openweathermap.org/data/2.5/weather?q=",
key: "&appid=xxxxx"
}
function handleSearchCity(e) {
e.preventDefault()
setCity(e.target.value)
}
async function searchWeathers(e) {
e.preventDefault()
console.log()
var response = await axios.get(API.link + city + API.key)
console.log(response)
setWeathers(response.data)
}
return (
<div>
<input value={city} onChange={handleSearchCity} />
<button onClick={searchWeathers}>Search</button>
{weathers && <Weather name={weathers.name} />}
</div>
)
}
export default Weathers;
Youssouf Oumar
2022-03-05
由于 weathers 被初始化为一个空数组,因此您实际上不应该收到错误
weathers.map 不是函数
。
也许您可以添加条件渲染,以便仅在从 API 获取天气数据时返回 jsx 表达式。
return weathers && (
<div>
// ...
</div>
)
}
export default Weathers;
Ikdemm
2022-03-04