从对象数组中删除单个对象
2022-10-04
97
我有以下对象集合,我使用 Object.values 将其转换为对象数组。
let demoObject = {
"abc": {
"ADMISSION_ID": 1632881,
"ADDITIONAL_DATA": null,
"CREATED_BY": "7348500"
},
"def": {
"ADMISSION_ID": 1632790,
"ADDITIONAL_DATA": null,
"CREATED_BY": "7348500"
},
"ijk": {
"ADMISSION_ID": 1619783,
"ADDITIONAL_DATA": null,
"CREATED_BY": "7346831"
}
}
const myArray = [];
Object.values(demoObject).forEach(val =>
myArray.push({
id: val.ADMISSION_ID,
header: val.HOSPITAL_GROUP_ID,
date: val.CREATED_DATE
})
);
我想根据“id”从数组中删除一个对象。
这是我到目前为止所做的,但它没有 工作 :
const deleteObject = (id) => {
myArray.value.findIndex((array) => array.id == id);
}
deleteObject(1632881)
Uncaught TypeError: Cannot read properties of undefined (reading 'findIndex')
3个回答
首先,
myArray.value.findIndex
是错误的;它应该是
myArray.findIndex
。
您可以按照以下代码片段使用 splice 函数删除索引
let demoObject = { "abc":
{
"ADMISSION_ID" : 1632881,
"ADDITIONAL_DATA" : null,
"CREATED_BY" : "7348500"
},
"def": {
"ADMISSION_ID" : 1632790,
"ADDITIONAL_DATA" : null,
"CREATED_BY" : "7348500"
},
"ijk":{
"ADMISSION_ID" : 1619783,
"ADDITIONAL_DATA" : null,
"CREATED_BY" : "7346831"
}}
const myArray = [];
Object.values(demoObject).forEach(val =>
myArray.push({id: val.ADMISSION_ID, header: val.HOSPITAL_GROUP_ID, date: val.CREATED_DATE})
);
const deleteObject = (id) => {
const index = myArray.findIndex(array => array.id === id)
myArray.splice(index, 1)
console.log(myArray)
}
deleteObject(1632881)
otejiri
2022-10-04
您需要为此创建一个函数吗?如果不需要,我建议您改用过滤方法。试试这个:
yourArrayOfObjects.filter(object => {
object.id !== id
})
Marat
2022-10-04
此方法遍历对象中的键并删除匹配的 ID。如果 ID 是唯一的,您可以在删除后添加返回语句。
function deleteObject(id) {
for (let key in demoObject) {
if (demoObject[key].ADMISSION_ID === id) {
delete demoObject[key];
}
}
}
Ethan R
2022-10-04