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如何解决:TypeError:无法将未定义或空转换为对象

2016-09-28
14135

我正在创建一个 angular2 项目,并使用 ng2-uploader 作为文件上传插件。我想拖放到一个 div 上,同时在 div 内添加一个上传按钮。选择要上传的文件后,我收到错误 TypeError:无法将未定义或 null 转换为对象

Html 代码为:

<div [hidden]="!onUpload" ngFileDrop [options]="options" (onUpload)="handleUpload($event)" [ngClass]="{'file-over': hasBaseDropZoneOver}" (onFileOver)="fileOverBase($event)">
     <input type="file" ngFileSelect [options]="options" (onUpload)="handleUpload($event)">
     <p><span>Response: {{ uploadFile | json }}</span></p>
</div>

组件为:

import { Component, OnInit, NgModule, NgZone } from '@angular/core';

@Component({
  selector: 'app-fileselect',
  templateUrl: './fileselect.component.html',
  styleUrls: ['./fileselect.component.css']
})

export class FileSelectComponent implements OnInit {
  zone: NgZone;
  hasBaseDropZoneOver: boolean = false;
  basicProgress: number = 0;
  uploadFile: any;

constructor() {
    this.zone = new NgZone({ enableLongStackTrace: false });//file upload    
  }

options: Object = {
    url: 'http://localhost:4200/assets/documents'
  };

handleUpload(data): void {
    if (data && data.response) {
      data = JSON.parse(data.response);
      this.uploadFile = data;
      this.zone.run(() => {
        this.basicProgress = data.progress.percent;
      });
    }
  } 

fileOverBase(e: any): void {
        this.hasBaseDropZoneOver = e;
      }
    }
2个回答

响应:{{ uploadFile | json } }

由于此结构,您会收到此错误,当您使用输入文件上传项目时,它将自动触发父 div ('ngFileDrop')。因此它将使用空数据调用该函数。此过程将导致错误。

因此,您可以做一件事,只需将输入按钮放在父 div 之外并尝试。它肯定会起作用。

    <div [hidden]="!onUpload" ngFileDrop [options]="options" (onUpload)="handleUpload($event)" [ngClass]="{'file-over': hasBaseDropZoneOver}" (onFileOver)="fileOverBase($event)">       
         <p><span>Response: {{ uploadFile | json }}</span></p>
    </div>
  <input type="file" ngFileSelect [options]="options" (onUpload)="handleUpload($event)">

现在,您可以使用一些 css 将输入按钮定位在 div 内。

只需检查一下。

Aswin KV
2016-10-05

在您的 html 代码中,选项后面缺少一个 "

您写道:

<input type="file" ngFileSelect [options]="options (onUpload)="handleUpload($event)">

您应该这样写:

<input type="file" ngFileSelect [options]="options" (onUpload)="handleUpload($event)">
StephaneM
2016-09-28