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TypeError:未定义不是一个对象(评估'data.filter') - React Native

2019-12-09
4675

我是 React/编程新手,在获取/显示数据时遇到问题。我的代码返回以下错误。提前感谢您的帮助。

TypeError:TypeError:undefined 不是对象(评估“data.filter”)

  import useFetch from 'react-fetch-hook'

  const { data } = useFetch('http://192.168.2.94:3000/list-categories')

  const locations = props.navigation.getParam('locationId')

  const displayedCategories = data.filter(      // ERROR HERE
    cat => cat.locId.indexOf(locations) >= 0
  )

  const renderGridItem = itemData => {
    return (
      <CategoryGridTile
        image={itemData.item.image}
        title={itemData.item.title}
      />
    )
  }

  return (
    <FlatList
      keyExtractor={(item, index) => item.id}
      data={displayedCategories}
      renderItem={renderGridItem}
    />
  )
}

JSON from http://192.168.2.94:3000/list-categories

2个回答

useFetch 返回一个 isLoading 标志以及数据,您必须使用该标志来显示加载指示器,直到数据可用

const { isLoading, data } = useFetch('http://192.168.2.94:3000/list-categories');
 if(isLoading) {
    return <span>Loading...</span>
 }
 const locations = props.navigation.getParam('locationId')

  const displayedCategories = data.filter(
    cat => cat.locId.indexOf(locations) >= 0
  )

  const renderGridItem = itemData => {
    return (
      <CategoryGridTile
        image={itemData.item.image}
        title={itemData.item.title}
      />
    )
  }

  return (
    <FlatList
      keyExtractor={(item, index) => item.id}
      data={displayedCategories}
      renderItem={renderGridItem}
    />
  )
Shubham Khatri
2019-12-09

我认为开始时没有数据,因此请使用默认分配

  const { data = [] } = useFetch('http://192.168.2.94:3000/list-categories')

更新

  const displayedCategories = data.filter(
    cat => cat && cat.locId && cat.locId.indexOf(locations) >= 0
  )
Jay
2019-12-09