我尝试在 React Native 中通过将值从一个屏幕传递到另一个屏幕来从一个屏幕导航到另一个屏幕，但是我收到了上述错误。理想情况下，我希望从平面列表中发送值，我试图实现一个可点击的平面列表，它将参数从选定行传递到另一个屏幕。

//index.js

import React from 'react';
import { StyleSheet, Button, Text, View, FlatList, TouchableHighlight } from 'react-native';

const ComponentsScreen = ({ navigation }) => {

  //example for detail scree
  return (
    <View>
    <FlatList
           data={[
             { key: 'Task 1' },
             { key: 'Task 2' },
             { key: 'Task 3' },
             { key: 'Task 4' },
             { key: 'Task 5' },
           ]}
           renderItem={({ item }) => {
               return (
                 <TouchableHighlight
                        onPress={() =>
                        navigation.navigate('Next', { message: 'hello from screen 1' })}
                 >
                      <Text >{item.key}</Text>
                 </TouchableHighlight>
               );
             }
           }

    />

    <Button
        onPress={() => navigation.navigate('NextScreen')}
        title="Go to ImageScreen"
    />
    </View>
  );
};
const styles = StyleSheet.create({
textStyle: {
  fontSize: 30
}
});

export default ComponentsScreen;

//NextScreen.js

  import React from 'react';
import { Text, View } from 'react-native';

//example for detail screen
const NextScreen = (route) => {
const { message } = route.params;

    return (
        <View>
          <Text>message: {JSON.stringify(message)}</Text>
        </View>
    );
};

export default NextScreen;

app.js

import React, { Component } from 'react';
import { createAppContainer } from 'react-navigation';
import { createStackNavigator } from 'react-navigation-stack';
import Index from './screens/Index';
import NextScreen from './screens/NextScreen';


const navigator = createStackNavigator({
  Home: Index,
  Next: NextScreen
},
{
  initialRouteName: 'Home',
  defaultNavigationOptions: {
    title: 'App'
  }
}
);

export default createAppContainer(navigator);