开发者问题收集

对象尚未被读取 node.js

2018-04-27
47

我有一个对象 db_parsed

当我运行 console.log(JSON.stringify(db_parsed, null, 4))

结果是:

{
    "data": [
        [
            {
                "name": "Me",
                "age": 23,
                "sex": "M"
            },
            {
                "name": "Wonderwoman",
                "age": 22,
                "sex": "F"
            }
        ],
        [
            {
                "name": "ALbert The Man",
                "age": 22,
                "sex": "M"
            }
        ],
        [
            {
                "name": "Leonard Johnson",
                "age": 23,
                "sex": "M"
            }
        ]
    ]
}

但是当我运行 console.log(db_parsed.data.filter(obj => obj.age === 22))

结果是 []

为什么?我遗漏了什么?我该如何解决这个问题?

2个回答

db_parsed.data 是一个包含 数组 的数组。

第二级数组包含对象。

您的过滤器代码试图处理这些对象,并且直接位于 db_parsed.data 内,而不是位于 db_parsed.data[0]db_parsed.data[1]db_parsed.data[2] 内。

您可以使用 reduce 将所有第二级数组连接成一个,然后对其进行过滤。

var db_parsed = {
  "data": [
    [{
        "name": "Me",
        "age": 23,
        "sex": "M"
      },
      {
        "name": "Wonderwoman",
        "age": 22,
        "sex": "F"
      }
    ],
    [{
      "name": "ALbert The Man",
      "age": 22,
      "sex": "M"
    }],
    [{
      "name": "Leonard Johnson",
      "age": 23,
      "sex": "M"
    }]
  ]
};

console.log(db_parsed.data.reduce((a,b) => a.concat(b), []).filter(obj => obj.age === 22))
Quentin
2018-04-27

您可以执行 [].concat.apply([], db_parsed.data) 然后过滤对象数组:

const db_parsed = {"data": [[{"name": "Me","age": 23,"sex": "M"},{"name": "Wonderwoman","age": 22,"sex": "F"}],[{"name": "ALbert The Man","age": 22,"sex": "M"}],[{"name": "Leonard Johnson","age": 23,"sex": "M"}]]};
const result = [].concat.apply([], db_parsed.data).filter(obj => obj.age === 22);

console.log(result);
Yosvel Quintero
2018-04-27