React & Redux:无法读取未定义的属性
我正在尝试用 React 编写应用程序,并且面临着必须管理如此多组件的状态的问题,因此我想使用 Redux。据我所知,Redux 不适用于根组件,因此我创建了一个名为“wrapper”的中间组件,它将包装所有内容并管理我的应用程序的状态。所以现在我有了我的原始根组件和一个包装器组件。我正尝试使用 Redux 在此包装器组件中获取一些道具,但由于某种原因,道具没有填充,我无法弄清楚。
这是我的代码:
import * as React from 'react'
import { Provider } from "react-redux";
import { connect } from "react-redux";
//SPFX references
import { DefaultButton, IButtonProps } from 'office-ui-fabric-react/lib/Button';
import { Panel, PanelType } from 'office-ui-fabric-react/lib/Panel';
//custom references
import { IRootProps } from '../props/IRootProps'
import { IRootState } from '../states/IRootState'
import { ITile, ITileHeader, ITileItem } from '../props/ITileStructure'
import store from '../main/store'
import { openPanel, closePanel } from '../actions/panelAction'
//Styles references
import rootStyles from '../styles/RooComponent.module.scss'
import commonStyles from '../styles/common.module.scss'
//Components references
import PanelComponent from './PanelComponent'
import FooterComponent from './FooterComponent'
import DiscardChangesDialogComponent from './DiscardChangesDialogComponent'
import BladesRootComponent from './BladesRootComponent'
import TilesListComponent from './TilesListComponent'
class RootComponent extends React.Component<{}, {}>{
tiles: ITile[] = [];
constructor(props) {
super(props);
}
render(): JSX.Element {
return (
<Provider store={store}>
<AppWrapper />
</Provider>
)
}
}
class AppWrapper extends React.Component<IRootProps, IRootState>{
tiles: ITile[] = [];
constructor(props: IRootProps) {
super(props);
if (this.tiles.length === 0) {
for (let i = 0; i < 200; i++) {
this.tiles.push({
key: i,
tileName: 'tile ' + i,
tileImageUrl: 'image url ' + i,
tileOrder: i,
headers: []
});
}
}
}
render(): JSX.Element {
return (
<div className="RootComponent">
<DefaultButton onClick={() => this.props.panelProps.openPanel()} className={commonStyles.defaultButton} >Configure Tiles</DefaultButton>
<Panel
isOpen={this.props.panelProps.isPanelOpen}
// tslint:disable-next-line:jsx-no-lambda
onDismiss={() => {
this.setState({ showPanel: false })
}}
type={PanelType.extraLarge}
headerText="Tiles configuration"
hasCloseButton={false}>
<PanelComponent />
</Panel>
</div>
)
}
}
let mapStateToProps = (state) => {
return {
panelProps: state.panel,
};
};
let mapDispatchToProps = (dispatch) => {
return {
openPanel: () => {
dispatch(openPanel());
}
};
};
connect(mapStateToProps, mapDispatchToProps)(AppWrapper);
export default RootComponent;
这是 ../main/store 的代码:
import {createStore, combineReducers} from 'redux';
import {Store} from 'redux';
import panel from "../reducers/panelReducer";
let store = createStore(
combineReducers({
panel
}),
{}
);
export default store;
而 ../reducers/panelReduce 看起来像这样:
//(state, action) =>
const panelReducer = (state = {
isPanelOpen: false
}, action) => {
switch (action.type) {
case "OPEN_PANEL":
state = {
...state,
isPanelOpen: true
};
break;
case "CLOSE_PANEL":
state = {
...state,
isPanelOpen: false
};
break;
}
return state;
};
export default panelReducer;
但是,代码正在执行,在行:
<Panel
isOpen={this.props.panelProps.isPanelOpen
它告诉我无法访问未定义的 isPanelOpen。​​由于某种原因,Redux 未以正确的方式连接。
P.S 我还是 Redux 的初学者,所以我可能做错了,如果有人能指出正确的方向。
实际上,您没有在
RootComponent
中使用连接的
AppWrapper
组件
您可以创建一个常量 AppWrapperConnected:
const AppWrapperConnected = connect(mapStateToProps, mapDispatchToProps)(AppWrapper);
并在
RootComponent
中使用
<AppWrapperConnected/>
此外,我认为如果将
RooComponent
和
AppWrapper
拆分为两个单独的文件,维护起来会更容易
另一个建议是像这样重写
mapStateToProps
let mapStateToProps = (state) => state.panel
因此,您可以直接使用
this.props.isPanelOpen
,我认为
panelProps
在这里没用