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Vue.JS - TypeError:无法使用“in”运算符在 Laravel 对象中搜索“undefined”

2019-12-15
9732

我想将一个对象从 Laravel 传递到 Vue.js,然后在 :v-for="option in this.options" 中使用它。我能够将对象从我的 Laravel blade 传递到 Vue.js 组件并将其显示在控制台中,但是当我想在 v-for 中使用该对象时,我收到此错误:

TypeError: Cannot use 'in' operator to search for 'undefined' in [{"id":1,"poll_id":1,"content":"Black","created_at":"2019-12-15 02:53:52","updated_at":"2019-12-15 02:53:52"},{"id":2,"poll_id":1,"content":"Blue","created_at":"2019-12-15 02:53:52","updated_at":"2019-12-15 02:53:52"}]
    at Proxy.render (app.js:48972)
    at VueComponent.Vue._render (app.js:52735)
    at VueComponent.updateComponent (app.js:53251)
    at Watcher.get (app.js:53662)
    at new Watcher (app.js:53651)
    at mountComponent (app.js:53258)
    at VueComponent../node_modules/vue/dist/vue.common.dev.js.Vue.$mount (app.js:58228)
    at VueComponent../node_modules/vue/dist/vue.common.dev.js.Vue.$mount (app.js:61113)
    at init (app.js:52315)
    at createComponent (app.js:55157)

Vue.JS 组件

<template>
    <div :v-for="option in this.options">
        <div v-if="option" class="option mt-4">
            {{ option }}
        </div>
    </div>
</template>

<script>
    export default {
        props: [
            'id', 'options'
        ],
        mounted() {
            this.options = JSON.parse(this.options);
            console.log(this.options);
        },
    }
</script>

Laravel blade

<options :id="{{ $poll->id }}" :options="'{{ json_encode($poll->options) }}'"></options>

console.log(this.options) 返回

(2) [{…}, {…}, __ob__: Observer]
    0: {…} // id, poll_id, content, created_at, updated_at
    1: {…} // id, poll_id, content, created_at, updated_at
    length: 2
    __ob__: Observer {value: Array(2), dep: Dep, vmCount: 0}
    __proto__: Array
1个回答

此块中有几个错误:

<div :v-for="option in this.options">
   <div v-if="option" class="option mt-4">
       {{ option }}
   </div>
</div>

您必须修复以下内容:

  • :v-for 更改为 v-for
  • this.options 中删除 this. ,因为您只应在 script 区域中使用 this.

  • 将整个块放入另一个 <div> 中,因为 <template> 标记内应该只有一个元素。因此,由于您使用的是循环,因此将呈现多个元素

AlekseyHoffman
2019-12-15