Question

输出是字符串，我想从数组中获取数据

2019-09-01

93

javascript

因此，我从一个数组中获取索引，它返回多个索引。我希望这些索引能够从另一个数组中获取数据。

  let withAccent = array.map(x => x.TERM);
  let withoutAccent = terms
    .map(x => x.TERM)
    .join(",")
    .normalize("NFD")
    .replace(/[\u0300-\u036f]/g, "")
    .split(",");
  let withoutAccentPosition = withoutAccent
    .map((withoutAccent, idx) =>
      withoutAccent.includes(input) ? "withAccent[" + idx + "]" : null
    )
    .filter(e => e !== null)
    .join(", ");
  console.log(withoutAccentPosition);
  console.log(withAccent[0], withAccent[1], withAccent[22]);

withAccent;

[ "ahoj", "test1", "test2", "test3", "test4", "test5", "můžete", "nebo", "pak", "postupně", … ]

withoutAccent:

[ "ahoj", "test1", "test2", "test3", "test4", "test5", "muzete", "nebo", "pak", "postupne", … ] Input is what user types

现在，我从 withoutAccent 中获取索引，并且我希望根据 with Accent 中的索引获取数据

因此，第一个日志返回 withAccent[] 位置的字符串，第二个日志运行正常，但我想要 withoutAccentPosition 中的数据。

Answer 1

如果您需要获取数组，则不应使用 join() 。 join() 方法通过连接数组中的所有元素来创建并返回一个新字符串。

以下是解决方案

var input = 'muzete' ;

var withAccent =[ "ahoj", "test1", "test2", "test3", "test4", "test5", "můžete", "nebo", "pak", "postupně"];
var withoutAccent =  [ "ahoj", "test1", "test2", "test3", "test4", "test5", "muzete", "nebo", "pak", "postupne" ];

let withoutAccentPosition = withoutAccent
    .map((withoutAccent, idx) =>
        withoutAccent.includes(input) ? "withAccent[" + idx + "]" : null
    ).filter(e => e !== null);
console.log(withoutAccentPosition);
console.log(withAccent[0], withAccent[1], withAccent[22]);

如果您需要直接值，则直接使用 withAccent[idx]，而不是将其设为字符串类型

var input = 'muzete' ;

var withAccent =[ "ahoj", "test1", "test2", "test3", "test4", "test5", "můžete", "nebo", "pak", "postupně"];
var withoutAccent =  [ "ahoj", "test1", "test2", "test3", "test4", "test5", "muzete", "nebo", "pak", "postupne" ];

let withoutAccentPosition = withoutAccent
    .map((withoutAccent, idx) =>
        withoutAccent.includes(input) ? withAccent[idx] : null
    ).filter(e => e !== null);
console.log(withoutAccentPosition);
console.log(withAccent[0], withAccent[1], withAccent[22]);