您只需使用一个正则表达式即可满足您的要求。您可以尝试以下正则表达式：

^(?=\D\d)(?=[^A-Z]*[A-Z])(?=[^a-z]*[a-z])(?=[^-!@._*#%]*[-!@._*#%])[-A-Za-z0-9=!@._*#%]*$

上述正则表达式的解释：

^, $ - Denotes the start and end of the line respectively.

(?=\D*\d) - Represents a positive look-around which asserts for at least a digit.

(?=[^A-Z]*[A-Z]) - Represents a positive look-around which asserts for at least an upper case letter.

(?=[^a-z]*[a-z]) - Represents a positive look-around which asserts for at least a lower case letter.

(?=[^-!@._*#%]*[-!@._*#%]) - Represents a positive look-around which asserts for at least a symbol among the listed. You can add more symbols according to your requirement.

[-A-Za-z0-9=!@._*#%]* - Matches zero or more among the listed characters. You can add more symbols accordingly.

您可以在 此处

上述正则表达式在 javascript 中的实现示例：

const myRegexp = /^(?=[^\d\n]*\d)(?=[^A-Z\n]*[A-Z])(?=[^a-z\n]*[a-z])(?=[^-!@._*#%\n]*[-!@._*#%])[-A-Za-z0-9=!@._*#%]*$/gm; // Using \n for demo example. In real time no requirement of the same.
const myString = `thisisSOSmepassword#
T#!sIsS0om3%Password
thisisSOSmepassword12
thisissommepassword12#
THISISSOMEPASSWORD12#
thisisSOMEVALIDP@SSWord123
`;
// 1. doesn't contain a digit --> fail
// 3. doesn't contain a symbol --> fail
// 4. doesn't contain an Upper case letter --> fail
// 5. doesn't contain a lowercase letter --> fail
let match;
// Taken the below variable to store the result. You can use if-else clause if you just want to check validity i.e. valid or invalid.
let resultString = "";
match = myRegexp.exec(myString);
while (match != null) {
  resultString = resultString.concat(match[0] + "\n");
  match = myRegexp.exec(myString);
}
console.log(resultString);

参考文献：

1. 推荐阅读： 原理对比。