Next-Auth 具有以下示例，它非常适合函数，但是我有一个类，需要在其中运行 const { data: session } = useSession() 。我想知道如何转换它以使其在类中有效？

export default function AdminDashboard() {
  const { data: session } = useSession()
  // session is always non-null inside this page, all the way down the React tree.
  return "Some super secret dashboard"
}

AdminDashboard.auth = true

我尝试将 session: useSession() 添加到以下构造函数中，但没有成功。

我的类

export default class AdminDashboard extends React.Component {
 constructor(props) {
        super(props);
        this.state = {
          value: null,
          areas:[],
          areasid:[],
          users: [],
          isLoading: true,
          isAreaLoading: true,
          session: useSession() // THIS DID NOT WORK
        };
        this.checkAnswer = this.checkAnswer.bind(this);
        
      }
}
AdminDashboard.auth = true

基于以下答案。我将脚本更改为如下形式

const withSession = (Component) => (props) => {
  const session = useSession()

  // if the component has a render property, we are good
  if (Component.prototype.render) {
    return <Component session={session} {...props} />
  }

  // if the passed component is a function component, there is no need for this wrapper
  throw new Error(
    [
      "You passed a function component, `withSession` is not needed.",
      "You can `useSession` directly in your component.",
    ].join("\n")
  )
}



export default class NewCampaign extends React.Component {
render(){
        const { data: session, status } = this.props.session;
        const { isLoading, users, areas, areasid, isAreaLoading } = this.state;
        return (
            <React.Fragment></React.Fragment>
         )}
}

const ClassComponentWithSession = withSession(NewCampaign)

NewCampaign.auth = false;

NewCampaign.getLayout = function getLayout(page) {
  return (
    <Dashboard>
      {page}
    </Dashboard>
  )
}

但是，我收到无法解构“this.props.session”属性“数据”的提示，因为它未定义。