使用 webworker 和 canvas 合并 png 图像
2015-01-22
1020
我试图利用 Web Worker 将 png 数组合并为具有透明度的单个图像,就像 Photoshop 合并多个图层时所做的那样。
我这样做的原因是我只将组合的结果保存到 indexeddb 中以供离线使用,之后我将在我的 three.js 应用中使用该图像创建纹理。
场景是大约有 400 种产品,3D 平面(产品)上的纹理 - 图像是 3 个图像(产品标题、价格和产品图像)的混合。
到目前为止我已经实现了这一点,但图像处理并不是那么好,我想知道如果我将
imageData.data
传递给 Web Worker,我该如何使用它来做到这一点。>
这是我目前所拥有的,但我无法使其工作。 (目前无需使用 webworker 即可完成此操作,只是尝试使合并工作)
var images = [];
var imageData = [];
images.push( function ( callback ) {
var mobile = new Image();
mobile.onload = function () {
console.log( "mobile loaded" );
callback( null, mobile );
};
mobile.onerror = function ( e ) {
console.log( "mobile error" );
callback( e, null );
};
mobile.src = "mobile.png";
} );
images.push( function ( callback ) {
var text = new Image();
text.onload = function () {
console.log( "text loaded" );
callback( null, text );
};
text.onerror = function ( e ) {
console.log( "text error" );
callback( e, null );
};
text.src = "text.png";
} );
async.series( images, function ( err, results ) {
if ( err ) {
console.error( err );
} else {
console.log( results );
getImageData( results );
}
} );
var getImageData = function ( images ) {
for ( var i = 0; i < images.length; i++ ) {
var canvas = document.createElement( 'canvas' );
canvas.width = 512;
canvas.height = 512;
var ctx = canvas.getContext( '2d' );
ctx.drawImage( images[ i ], 0, 0 );
imageData.push( ctx.getImageData( 0, 0, canvas.width, canvas.height ).data );
}
merge( imageData );
};
var merge = function ( data ) {
var merged = [];
var mixFactor = 0.5;
//var newPixel = imageMainPixel * mixFactor + imageSecPixel * ( 1 - mixFactor )
//for ( var i = 0, len = data.length; i < len; i++ ) {
for ( var j = 0, byteLen = data[ 0 ].length; j < byteLen; j += 4 ) {
var r = data[ 0 ][ j ] * mixFactor + data[ 1 ][ j ] * ( 1 - mixFactor );
var g = data[ 0 ][ j + 1 ] * mixFactor + data[ 1 ][ j + 1 ] * ( 1 - mixFactor );
var b = data[ 0 ][ j + 2 ] * mixFactor + data[ 1 ][ j + 2 ] * ( 1 - mixFactor );
var a = data[ 0 ][ j + 3 ] * mixFactor + data[ 1 ][ j + 3 ] * ( 1 - mixFactor );
merged[ j ] = r;
merged[ j + 1 ] = g;
merged[ j + 2 ] = b;
merged[ j + 4 ] = a;
}
//}
var canvas = document.getElementById( 'canvas' );
canvas.width = 512;
canvas.height = 512;
var ctx = canvas.getContext( '2d' );
var imageData = ctx.createImageData( 512, 512 );
imageData.data.set( merged );
ctx.putImageData( imageData, 0, 0 );
};
我目前收到的错误是:
Uncaught RangeError: Source is too large
更新
我设法通过将合并函数更改为以下内容来合并图像:
var merge = function ( data ) {
var canvas = document.getElementById( 'canvas' );
canvas.width = 512;
canvas.height = 512;
var ctx = canvas.getContext( '2d' );
var imageData = ctx.createImageData( 512, 512 );
var mixFactor = 0.5;
for ( var j = 0, byteLen = data[ 0 ].length; j < byteLen; j += 4 ) {
imageData.data[ j ] = data[ 0 ][ j ] * mixFactor + data[ 1 ][ j ] * ( 1 - mixFactor );
imageData.data[ j + 1 ] = data[ 0 ][ j + 1 ] * mixFactor + data[ 1 ][ j + 1 ] * ( 1 - mixFactor );
imageData.data[ j + 2 ] = data[ 0 ][ j + 2 ] * mixFactor + data[ 1 ][ j + 2 ] * ( 1 - mixFactor );
imageData.data[ j + 3 ] = data[ 0 ][ j + 3 ] * mixFactor + data[ 1 ][ j + 3 ] * ( 1 - mixFactor );
}
console.log( imageData.data.length );
ctx.putImageData( imageData, 0, 0 );
};
结果就像 2 幅图像都具有 50% 的不透明度。但这不是想要的结果。我希望图像充当图层,就像多个 png 一个在另一个之上一样...如果最上面的图像有透明的地方,您应该能够看到它下面的图像。
也许我应该根据 alpha 值进行绘制?
3个回答
经过一番思考,我最终检查了每个像素的 alpha 值,并设法实现了我想要的结果。我重写了合并函数,如下所示:
var merge = function ( data ) {
var canvas = document.getElementById( 'canvas' );
canvas.width = 512;
canvas.height = 512;
var ctx = canvas.getContext( '2d' );
var imageData = ctx.createImageData( 512, 512 );
var mixFactor = 0.5;
for ( var j = 0, byteLen = data[ 0 ].length; j < byteLen; j += 4 ) {
// imageData.data[ j ] = data[ 0 ][ j ] * mixFactor + data[ 1 ][ j ] * ( 1 - mixFactor );
// imageData.data[ j + 1 ] = data[ 0 ][ j + 1 ] * mixFactor + data[ 1 ][ j + 1 ] * ( 1 - mixFactor );
// imageData.data[ j + 2 ] = data[ 0 ][ j + 2 ] * mixFactor + data[ 1 ][ j + 2 ] * ( 1 - mixFactor );
// imageData.data[ j + 3 ] = data[ 0 ][ j + 3 ] * mixFactor + data[ 1 ][ j + 3 ] * ( 1 - mixFactor );
imageData.data[ j ] = ( data[ 1 ][ j + 3 ] === 0 ? data[ 0 ][ j ] : data[ 1 ][ j ] );
imageData.data[ j + 1 ] = ( data[ 1 ][ j + 3 ] === 0 ? data[ 0 ][ j + 1 ] : data[ 1 ][ j + 1 ] );
imageData.data[ j + 2 ] = ( data[ 1 ][ j + 3 ] === 0 ? data[ 0 ][ j + 2 ] : data[ 1 ][ j + 2 ] );
imageData.data[ j + 3 ] = ( data[ 1 ][ j + 3 ] === 0 ? data[ 0 ][ j + 3 ] : data[ 1 ][ j + 3 ] );
}
console.log( imageData.data.length );
ctx.putImageData( imageData, 0, 0 );
};
仍需要进行一些改进,但我想现在我能够在 Web Worker 中合并图像 :)
0x_Anakin
2015-01-22
修改后的代码为:
for ( var j = 0, byteLen = data[0].length; j < byteLen; j += 4 )
{
var rA = data[0][j], rB = data[1][j];
var gA = data[0][j+1], gB = data[1][j+1];
var bA = data[0][j+2], bB = data[1][j+2];
var aA = data[0][j+3], aB = data[1][j+3];
var rOut = (rA * aA / 255) + (rB * aB * (255 - aA) / (255*255));
var gOut = (gA * aA / 255) + (gB * aB * (255 - aA) / (255*255));
var bOut = (bA * aA / 255) + (bB * aB * (255 - aA) / (255*255));
var aOut = aA + (aB * (255 - aA) / 255);
imageData.data[j] = rOut;
imageData.data[j+1] = gOut;
imageData.data[j+2] = bOut;
imageData.data[j+3] = aOut;
}
这是解决方案(Alpha 混合) 如何混合两个 ARGB 像素?
slaviboy
2017-10-13
我编写了 一个处理这个问题的库 。不仅如此,它还能处理阴影和图块。
Robert Plummer
2015-05-04