tabulator 没有找到匹配选择器的元素
2019-03-07
3111
尝试第一个超级基础制表符,但控制台错误“未找到与选择器匹配的元素”。我尝试了几个不同的示例,但不知道我做错了什么。命名应该是这样的吗?
<html>
<head><title>Test for tabulator</title>
<link href="dist/css/tabulator.min.css" rel="stylesheet">
<script type="text/javascript" src="dist/js/tabulator.min.js"></script>
<script>
//define data
var tabledata = [
{id:1, name:"Oli Bob", location:"United Kingdom", gender:"male", rating:1, col:"red", dob:"14/04/1984"},
{id:2, name:"Mary May", location:"Germany", gender:"female", rating:2, col:"blue", dob:"14/05/1982"},
{id:3, name:"Christine Lobowski", location:"France", gender:"female", rating:0, col:"green", dob:"22/05/1982"},
{id:4, name:"Brendon Philips", location:"USA", gender:"male", rating:1, col:"orange", dob:"01/08/1980"},
{id:5, name:"Margret Marmajuke", location:"Canada", gender:"female", rating:5, col:"yellow", dob:"31/01/1999"},
{id:6, name:"Frank Harbours", location:"Russia", gender:"male", rating:4, col:"red", dob:"12/05/1966"},
{id:7, name:"Jamie Newhart", location:"India", gender:"male", rating:3, col:"green", dob:"14/05/1985"},
{id:8, name:"Gemma Jane", location:"China", gender:"female", rating:0, col:"red", dob:"22/05/1982"},
{id:9, name:"Emily Sykes", location:"South Korea", gender:"female", rating:1, col:"maroon", dob:"11/11/1970"},
{id:10, name:"James Newman", location:"Japan", gender:"male", rating:5, col:"red", dob:"22/03/1998"},
];
//define table
var table = new Tabulator("#example-table", {
data:tabledata,
autoColumns:true,
});
</script>
</head>
<body>
<h1>test tabulator </h1>
<div id="example-table"></div>
</body>
</html>
我是否遗漏了某些明显的东西?这是直接从示例中复制/粘贴的。
1个回答
是的,因为访问时该元素不存在。将您的 javascript 移到 div 后面,它应该可以工作。或者使用页面加载事件:
页面底部:
<div id="example-table"></div>
<script>
var table = new Tabulator("#example-table", {
data:tabledata,
autoColumns:true,
});
</script>
页面加载:
window.addEventListener("load", function() {
var table = new Tabulator("#example-table", {
data:tabledata,
autoColumns:true,
});
},false);
Ibu
2019-03-07