jQuery Remove 方法出错
2017-12-14
71
我是 Javascript/jQuery 的新手,正在尝试根据用户在表中的输入构建项目列表。
这里的想法是,用户将文本输入表单,js/jQuery 将捕获该数据并将其显示为 boostrap4 表中的一行。
我明白了,当用户输入时,它会将数据添加为一行(参见图片),但是,我需要它工作这样,当用户单击红色的“删除”按钮时,它会删除整个表行。现在,当我单击按钮时,它只会删除按钮(参见第三张图片)。
这是我的 HTML:
<div class="tab-pane fade" id="watchlist" role="tabpanel" aria-labelledby="watchlist-tab">
<h2 class="display-4">Watch List</h2>
<p class="lead">Add series to your watch list and receive an e-mail notification when new data is available.</p>
<p class="card-text">
<div class="form-check form-check-inline">
<span class="mr-2">How would you like to receive your e-mail notifications?</span>
<label class="form-check-label" data-toggle="tooltip" data-placement="top" title="Get email updates on your series bundled in one single daily email.">
<input class="form-check-input" type="radio" name="inlineRadioOptions" id="inlineRadio1" value="option1"> Daily Digest
</label>
</div>
<div class="form-check form-check-inline" data-toggle="tooltip" data-placement="top" title="Get an email instantly when new data is released. You will not get a second email until you've downloaded the most recent data.">
<label class="form-check-label">
<input class="form-check-input" type="radio" name="inlineRadioOptions" id="inlineRadio2" value="option2"> Individually
</label>
</div>
</p>
<p class="card-text mt-2">
<form class="add-items">
<div class="form-row align-items-center">
<div class="col-md-6">
<input type="text" class="form-control mb-2 mb-sm-0" id="watchlist-item" placeholder="Search series by name or symbol...">
</div>
<div class="col-auto">
<button type="submit" class="btn btn-dark" style="margin-left:-12px">Add to Watch List</button>
</div>
</div>
</form>
</p>
<p class="card-text">
<table class="table table-sm table-hover">
<thead>
<tr>
<th scope="col">Symbol</th>
<th scope="col">Name <i class="ml-4 fa fa-sort" aria-hidden="true"></i></th>
<th scope="col">New Data? <i class="ml-4 fa fa-sort" aria-hidden="true" data-toggle="tooltip" data-placement="top" title="Sort data by latest release."></i></th>
<th scope="col"></th>
</tr>
</thead>
<tbody id="table-items">
</tbody>
</table>
</p>
</div>
</div>
这是我的 jQuery:
$(document).ready(function () {
$('.add-items').submit(function(event) {
event.preventDefault();
var item = $('#watchlist-item').val();
if (item) {
$('#table-items').append("<tr>S<td>" + item + "</td><td>S&P 500 Total Return Index</td><td><button class='btn btn-info'>Get Data</button></td><td><button class='btn btn-danger remove'>Remove</button></td></tr>")
$('#watchlist-item').val("");
}
});
$(document).on("click", ".remove", function() {
$(this).parent().remove();
});
});
1个回答
按钮位于
td
中,因此其父级是该
td
,而不是
tr
。使用两次
.parent()
调用以再向上一级,或使用
.closest("tr")
2017-12-14