我一直在编写一些 JavaScript 代码，并引入了这个小函数：function decodeLink(thelink) {console.log(typeof(thelink)); // Reports 'string'if (thelink.contains("something")) {// Cool condition}}但是，如果我要调用decodeLink("hello");，我会收
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我有以下函数：<div class="chat-box"></div>setInterval(() => {let xhr = new XMLHttpRequest();xhr.open("POST", "processes/get-chat.php", true);xhr.onload = ()=> {if(xhr.readyState === XMLHttpRequest.DONE) {if(
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